How Does Charge Affect Force in an Electric Field?

[ahero4eternity]

A small object carrying a charge of -5.50 nC is acted upon by a downward force of 24.0 nN when placed at a certain point in an electric field.

What would be the magnitude and direction of the force acting on a proton placed at this same point in the electric field?

Magnitude & Direction of the Electric Field = 4.36 N/C upward


F = k (Q1Q2/r^2)
F = |q|E
k = 9E9

F = |q|E
= 5.5E-9 x 4.36
= 2.398E-8

 

[ZPower]

"Magnitude & Direction of the Electric Field = 4.36 N/C upward"I think this is correct so far, and then all you need to do is multiply the E by the charge of a proton.

There is no need for k.

I think u pretty much got it, maybe # error.

 

[Shooting Star]

F = |q|E
= 5.5E-9 x 4.36
= 2.398E-8[/b]

If you have found the field yourself, then what do you think should put in place of q?