How Does Current Flow Through a Copper Wire?

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SUMMARY

The discussion focuses on calculating the total number of collisions that free electrons undergo in a copper wire carrying a current of 8.0A. The wire has a length of 3.00m and a diameter of 1.5mm, with a resistivity of 1.7 x 10-8 Ωm and a free electron concentration of 8.5 x 1028 m-3. The relevant equation for determining the number of collisions is derived from the Drude model, specifically m/(ρn²), where m is the mass of an electron, ρ is the resistivity, and n is the concentration of free electrons.

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  • Understanding of Ohm's Law
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  • Knowledge of basic physics concepts such as current, resistivity, and electron charge
  • Ability to perform calculations involving physical constants and units
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  • Explore the implications of Ohm's Law in practical applications
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Students studying physics, electrical engineers, and anyone interested in understanding the behavior of current flow in conductive materials like copper.

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Homework Statement






A current of I=8.0A is flowing in a typical extension cord of length L=3.00m. The cord is made of copper wire with diameter d=1.5mm.

The charge of the electron is e=1.6*10^-19C. The resisitivity of copper is \rho=1.7*10^-8\Omega m. The concentration of free electrons in copper is n=8.5*10^28m^-3



Homework Equations



I honestly have no idea. There's nothing in my book about collisions at all other than saying that's what causes resistance.

The Attempt at a Solution



Honestly have no idea where to begin... there is literally not a thing about this in my book. It's from an online homework assignment.
 
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hi aftershock! :smile:

erm :redface:what's the question? :confused:
 
tiny-tim said:
hi aftershock! :smile:

erm :redface:what's the question? :confused:

Wow I can't believe I left that part off, sorry.

Find the total number of collisions that all free electrons undergo in one second.

I was able to see the answer and the equation used was something along the lines of m/(\rhone2)

I have no idea where that came from though.
 
aftershock said:
Wow I can't believe I left that part off, sorry.

he he :biggrin:
Find the total number of collisions that all free electrons undergo in one second.

I was able to see the answer and the equation used was something along the lines of m/(\rhone2)

I have no idea where that came from though.

not something I'm familiar with :redface:, but you might get some help from http://en.wikipedia.org/wiki/Classical_and_quantum_conductivity#Classical_conductivity http://en.wikipedia.org/wiki/Drude_model or http://en.wikipedia.org/wiki/Ohm's_Law :smile:
 

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