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How does Faraday's law include self inductance?

  1. Dec 29, 2016 #1
    A varying magnetic flux causes an induced voltage (according to Faraday-Lenz law) that generates a current that generates a magnetic field that generates another magnetic flux in the same circuit. Does the Faraday-Lenz law include this self induction? In other words why cant we take that induced magnetic field and use it again inside lenz law?

    Another question, When you connect a battery to a circuit, and we graph Current versus time. The current slowly rises to the maximum current possible is this due to magnetic effects? or just transient state until the charges settle in to steady state?
     
  2. jcsd
  3. Dec 29, 2016 #2
    I don't understand, could you please explain what you mean?

    But maybe this will help
    http://booksite.elsevier.com/samplechapters/9780750679701/9780750679701.PDF (page 22 Understanding the Inductor)

    Yes, this rise is due to magnetic flux build up. This rise "stops" if we saturate the core (and jump to Vin/R_coil) or current reach value equal to Vin/R_coil or some other element (if we have an ideal inductor ) limits the current.
     
  4. Dec 29, 2016 #3
    Like isnt there an induced magnetic field going through the loop? Why not take it into account while calculating the change in flux? as if it was a 2nd magnetic field?


    About current, assume we turn off all the magnetic effects and there are no inductors. If we graph I and T will we get the same shape roughly like rising to maximum?
     
  5. Dec 30, 2016 #4

    NascentOxygen

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    Current in the coil modifies the magnetic field the coil finds itself in, and the field due to the current is directed so as to oppose that which gave rise to the current. In any case, the voltage induced is always determined by the rate of change of the net flux, the vector sum of all.

    In a circuit where there is no inductance, current is free to instantly jump from one value to another. Current doesn't have inertia, though you could say that current flowing in an inductor does seem to have inertia, although this is a property of the inductance rather than the current.
     
  6. Dec 30, 2016 #5
    "Rate of change of net flux". So why do we only consider the change of flux (Not from the loop, outside source of magnetic field) only?
    For example, dB/dt of a magnet affect a loop without considering the rate of change of the magnetic field induced by the loop?
     
  7. Dec 30, 2016 #6

    NascentOxygen

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    If there is not going to be much current in the coil (due to a high series resistance) then where the applied field is strong you may overlook B due to the coil's weak current. Otherwise, it will need to be taken into account.
     
  8. Dec 30, 2016 #7

    Merlin3189

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    I wonder if it might help to put this question into a context?
    It may be that in some cases people do consider the effect of secondary currents, but in a question where one is only asked to calculate the induced emf, no secondary current is required to flow?

    With a transformer the flux produced by the primary depends on the primary voltage and the primary inductance. A secondary emf is caused. If then a secondary current is allowed to flow, this would indeed counter the primary flux, but then the primary back emf would fall, allowing additional primary current flow to maintain the flux at the original level.
     
  9. Dec 30, 2016 #8
    But if lets say it is strong compared to to the applied B, Just for curiosity. In school, we always overlook the effect of that induced MF

    How would they calculate the rate of change of the induced MF as it depends on the applied MF? You would have to use the law twice or what?
     
  10. Dec 30, 2016 #9

    NascentOxygen

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    You'd combine Ohm's Law and Faraday's Law into a differential equation involving ##\mathsf{ \vec B}## and ##\mathsf{ \dfrac {d\vec {B}}{dt}}## and solve it.
     
  11. Dec 30, 2016 #10

    cnh1995

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    You'll need to use differential equations then, as NascentOxygen said earlier.

    In practice, this situation is observed in current transformers. In a CT, the net flux in the core is equal to primary flux-secondary flux. When the CT secondary is shorted or connected to a very low resistance burden, the secondary flux is almost equal to the primary flux. This leaves only a little flux in the core and hence the voltage induced in the secondary is also very small. If the secondary resistance is increased, secondary current decreases and hence, total flux in the core increases. This means the secondary voltage also increases. Further if you open circuited the secondary of a CT, there would be no secondary current and net core flux would be the primary flux only, which is very high. This will induce very high voltage across the CT secondary and could destroy the coils.
    Hence, an important precaution in CT operation is "never open circuit the secondary of a CT while in operation".
     
    Last edited: Dec 30, 2016
  12. Dec 30, 2016 #11
    Could you give an example? Just to confirm?
    But dont you have to use faraday's law neglecting the induced magnetic field to get a differential equation of the net field?
     
  13. Dec 31, 2016 #12
    The self inductance is included in Faraday's law, but it is subtle. The flux density "B" is the NET flux density, which is the superposition of external & internal due to loop current. For a superconductor ring immersed in an external B, the induced loop current generates an internal B equal & opposite to Bext. The net is zero. Since voltage around loop = -N*d (phi)/dt, there is zero E field inside the superconductor ring, consistent with Ohm's law, J = sigma*E.

    Claude
     
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