How Does Gauss's Law Explain Net Flux in Electric Fields?

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The discussion focuses on applying Gauss's Law to determine the net flux through a closed surface surrounding two charges, q and -q. With 24 electric field lines emanating from the positive charge and 15 terminating at the negative charge, the net flux is analyzed. Since the charges are equal in magnitude and opposite in sign, the net flux through the closed surface is concluded to be zero. A conceptual approach involves counting the lines entering and exiting the surface to confirm this result. Ultimately, Gauss's Law effectively illustrates that the net flux for a dipole configuration is zero.
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A figure showing electric field lines has two charges, q and -q. There are 24 lines emanating from the +q charge. 15 of these lines terminate at -q. There are 24 lines terminating at the q- charge. What is the net flux through the surface surrounding the two charges?
 
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Well it is a dipole with the two charges being of equal magnitude, so wouldn't the net flux be 0?
 
It's a closed surface right? Then just apply Gauss law. A more "conceptual" approach is to count how many lines are entering the closed surface and how many are exiting. Then find the net number of lines exiting the surface.
 

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