How Does Gravity Affect a Stone Thrown Downward?

AI Thread Summary
When a stone is thrown downward with an initial speed of 12.0 m/s, it retains that initial velocity as it falls. Gravity affects the stone by accelerating it downward at 9.8 m/s², increasing its velocity over time. The stone's speed will continue to rise as it falls, not decrease to 9.8 m/s. The acceleration due to gravity is the rate of change of the stone's velocity, meaning it will gain speed each second. Thus, the stone will have an initial speed of 12.0 m/s and will accelerate downward until it hits the ground.
bryans1mic
Messages
3
Reaction score
0
hello there, i had a question about a free fall question.

Problem states that a stone is thrown vertically downward with an initial
speed of 12.0 m/s from some tower.

well, i was wondering if i should use 12.0m/s or if i should use gravity (9.8 m/s)

will the rock have an initial speed of 12.0m/s then eventually become 9.8 m/s
or will it be 12.0 m/s until the rock hits the ground.


(all my book examples were throwing something upwards which is manageable but
going downward gots me stumped.)

thanks
 
Physics news on Phys.org
Hi bryans1mic, welcome to PF!

Be careful not to confuse velocity (m/s) with acceleration (m/s2). Objects in free fall (i.e. under the influence of gravity *only*) will accelerate downward at 9.8 m/s2. What this means is that although the object will start out with a velocity (initially) of 12.0 m/s downward, gravity will accelerate the stone so that its downward velocity increases (that's what acceleration is...the rate of change of velocity). Its velocity will increase by 9.8 m/s PER second. That's where the unit of m/s2 for acceleration comes from.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top