How Does Impulse Affect Particle Velocity?

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AI Thread Summary
The discussion centers on calculating the final velocity of a particle after a force is applied. Initially, the particle has a velocity of -6.3 m/s and a mass of 5.2 kg. The impulse applied is 42 Ns, leading to the equation 42 = 5.2(vF + 6.3). Solving this results in a final velocity (vF) of approximately 1.777 m/s. The calculations and method used are confirmed to be correct.
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Homework Statement


http://img401.imageshack.us/img401/46/impulsemw6.jpg

Before the force is applied (t<0), the particle moves along the x-axis with a velocity of -6.3 m/s.

Find the velocity of the particle after the force stops acting on it.

The particle has a mass of 5.2 kg

Homework Equations


j=\Deltap
\Deltap=0

The Attempt at a Solution


j=42Ns

j=\Deltap
42=mvF-mv0
42=(5.2)vF-5.2(-6.3)
9.24=5.2(v)F
vF=1.777 m/s
 
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Your method looks good.
 
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