How Does Inverting Inputs Affect a 3-Input XOR Gate?

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Inverting one input of a 3-input XOR gate changes the output but maintains the same number of combinations resulting in a zero output. The output can be expressed as a boolean equation, and inverting one input leads to a consistent output regardless of which input is inverted. The discussion suggests that the resulting gate could be an XNOR, but there is confusion about the correct boolean expression. Inverting all three inputs does not yield an XOR output, contradicting initial assumptions. The key takeaway is that the behavior of the XOR gate remains consistent with input inversions, but the output function changes.
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Homework Statement



An Xor gate has 3 inputs w x y and its output is z. If you invert one of the inputs, what will the output be? Show this in terms of a boolean expression and no matter which input you invert, the output will be the same.

What is this type of gate called?
Also, what happens if you invert all three inputs?

Homework Equations



w XOR x XOR y = z
w'x'y + w'xy' + w'xy + wx'y' + wx'y + wxy' = z => expanding xor using and or and not gates

The Attempt at a Solution



If you invert one of the inputs then still you will have 2 combinations of w,x,y for which z=0 and the rest of the input combinations =1. But I do not see how to find the new output function z when you invert one of the input and then find a special gate for that expression. Just out of guessing, I think the gate is XNOR because it is a special gate often used in boolean expressions. Also, if all the inputs are inverted then it would still be an xor right?
 
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hime said:
w'x'y + w'xy' + w'xy + wx'y' + wx'y + wxy' = z => expanding xor using and or and not gates
You sure about that? I thought it would be this:
w'x'y + w'xy' + wx'y' + wxy = z
for XOR.

hime said:
Also, if all the inputs are inverted then it would still be an xor right?
No, it wouldn't.
 
Last edited:

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