How Does Mass Affect Velocity in a Two-Ball Pendulum Collision?

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 3K views
chazgurl4life
Messages
52
Reaction score
0
Two balls, of masses mA = 32 g and mB = 80 g are suspended as shown in Figure 7-44. The lighter ball is pulled away to a 60° angle with the vertical and released.a) What is the velocity of the lighter ball before impact? (Take the right to be positive.)


a) What is the velocity of the lighter ball before impact? (Take the right to be positive.)

i have been using the formula V=M+m
---- X (2gl(1-cos of the angle)^1/2
m


so when i put it all together i get :

V= .08kg+.032Kg
---------- X (2*9.8*.3m*1-cos60 degrees)^1/2
.032 kg

V=3.5 X(2.94)^1/2
V=6 m/s

but apparently this answer is wrong ..can anyone help ??
 
Physics news on Phys.org
You solved too far. The answer is in your question.(modified slightly with brackets).
chazgurl4life said:
a) What is the velocity of the lighter ball before impact? (Take the right to be positive.)

[2gl(1-cos of the angle)]^1/2