How Does Matrix Transposition Affect the Product A^T A?

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SUMMARY

The discussion focuses on the matrix product B = A^T A and demonstrates that each element b_{ij} is calculated as the dot product of the i-th row of A^T and the j-th column of A. Specifically, it establishes that b_{ij} = a^{T}_{i} a_{j}, where a_{i} and a_{j} are column vectors from matrix A. The transposition of matrix A effectively switches its rows and columns, allowing for this dot product formulation.

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Let B=A^{T}A. Show that b_{ij}=a^{T}_{i}a_{j}.

I have no idea how to approach this problem.
 
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jtruth914 said:
Let B=A^{T}A. Show that b_{ij}=a^{T}_{i}a_{j}.

I have no idea how to approach this problem.
I don't understand your notation. Could you please clarify what you've written?
 
Let B=A^{T}A. Show that b_{ij}=a^{T}_{i}a_{j}.

When you transpose AYou are flipping the rows and columns.
When you multiply A^{T}A you would generate each element b_{ij} will be the dot product of row i of the first matrix and column j of the second matrix. Since the first matrix is the transposition of the second, row i of that transposition will be column i of the original. So each element will be the dot product of two column vectors:

b_{ij}=a_{i}·a_{j}

Using matrix notation, this is:

b_{ij}=a^{T}_{i}a_{j}
 

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