- #1
kidsasd987
- 143
- 4
1.
If we look at the equation above, it says
G(Vin-BVout)=Vout
but this equation is actually,G(Vin-BVout1)=Vout2
whereas Vout1 is Vout for first iteration and Vout2 is Vout for 2nd iteration.
Therefore, they must have different values.
How can we get the transfer function then?
2.
if we assume the very first iteration of the loop, V- will be greater than V+ as Vout>>>>>>>Vin.
At this point, V+-V- <0, therefore, it will generate a negative feedback opamp response.
and the next iteration vice versa.
How can we prove that if we proceed this iteration over and over, we will get the resultR2/(R1+R2)