How Does Non-Monatomic Gas Behavior Differ During Expansion?

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SUMMARY

The discussion focuses on the behavior of a non-monatomic gas during expansion, specifically analyzing the energy changes when the gas transitions from state I to state F. The internal energy formula U=3/2nRT is not applicable for non-monatomic gases, necessitating the use of the first law of thermodynamics. The energy added to the gas by heat is quantified as 424 J, and participants discuss calculating the change in internal energy (∆U) using the equation ∆U=Q+W. The work done by the gas during this process is critical for determining ∆U accurately.

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  • Understanding of the first law of thermodynamics
  • Familiarity with non-monatomic gas behavior
  • Ability to calculate work done by gases in thermodynamic processes
  • Knowledge of internal energy equations for different types of gases
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Students in thermodynamics, physics enthusiasts, and professionals dealing with gas behavior in engineering applications will benefit from this discussion.

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Homework Statement


A NON-monatomic gas expands from I to F in the Figure (Since it is not monatomic U=3/2nRT does not give you the internal energy, this only works for monatomic gases, instead you must use the first law). The energy added to the gas by heat is 424 J when the gas goes from I to F along the diagonal path.

Picture/Figure: http://www.webassign.net/sf/p12_05.gif


Homework Equations





The Attempt at a Solution


well i tried using ∆U=Q+W(on) and doing all the possible combinations of positive and negative (finding work from area under curve) but I couldn't get the correct answer for ∆U. I hope you can help!

thanks so much
--aweg
 
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You don't seem to have stated a question. Are you trying to find \Delta U?

What is the work done by the gas in going from I to F? Be careful about the units. It is then just a matter of subtracting the work done by the gas from the heat flow into the gas.

AM
 
Last edited:

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