Finding specific heat capacity of a non-monatomic (ideal gas)

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SUMMARY

The discussion focuses on calculating the specific heat capacity (Cp) of a non-monatomic ideal gas during an isobaric process. The user successfully determined the change in internal energy (ΔU) using the first law of thermodynamics, applying the formula ΔU = Q - PΔV. To find Cp, the relationship ΔH = Q and the equation Cp - Cv = R are utilized, where ΔH represents the change in enthalpy. The user is guided to use these equations to derive Cp from the provided heat and pressure-volume work values.

PREREQUISITES
  • Understanding of the first law of thermodynamics
  • Knowledge of ideal gas laws and properties
  • Familiarity with isobaric processes
  • Concept of molar specific heat capacities (Cp and Cv)
NEXT STEPS
  • Study the derivation of the first law of thermodynamics in isobaric processes
  • Learn about the specific heat capacities of different types of gases, including diatomic and polyatomic gases
  • Explore the relationship between enthalpy and internal energy for ideal gases
  • Investigate the implications of the ideal gas law in real-world applications
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Students studying thermodynamics, physicists, and engineers involved in heat transfer and gas behavior analysis.

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Homework Statement



Suppose that 31.4 J of heat is added to an ideal gas. The gas expands at a constant
pressure of 1.40x104 Pa while changing its volume from 3.00x104 to 8.00x104 m3.
The gas is not monatomic, so the relation CP = 5/2R does not apply. (a) Determine the
change in the internal energy of the gas. (b) Calculate its molar specic heat capacity
CP .

Homework Equations


The Attempt at a Solution



I have completed part a) using the knowledge that it is an isobaric process, but I'm a bit unsure of my answer for b)

My textbook says that for a diatomic ideal gas, Cp is given by 7/2 R, but the question only says the gas is not monatomic.

Is there a piece of info I'm missing?

Thanks!
 
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Because U is a state variable, you can define a path between the initial and final states of the gas where V is a constant. This will allow you to find cv, from which you can extract cp.
 
BOAS said:

Homework Statement



Suppose that 31.4 J of heat is added to an ideal gas. The gas expands at a constant
pressure of 1.40x104 Pa while changing its volume from 3.00x104 to 8.00x104 m3.
The gas is not monatomic, so the relation CP = 5/2R does not apply. (a) Determine the
change in the internal energy of the gas. (b) Calculate its molar specic heat capacity
CP .

Homework Equations





The Attempt at a Solution



I have completed part a) using the knowledge that it is an isobaric process, but I'm a bit unsure of my answer for b)

My textbook says that for a diatomic ideal gas, Cp is given by 7/2 R, but the question only says the gas is not monatomic.

Is there a piece of info I'm missing?

Thanks!
Just apply the constant pressure version of the first law: ΔU=Q-PΔV. Also, since ΔH=ΔU+Δ(PV), which for this constant pressure process becomes ΔH=ΔU+PΔV. So, for this process ΔH=Q. For an ideal gas, ΔH=CpΔT and ΔU=CvΔT. So,
ΔH/ΔU=Cp/Cv=(Q-PΔV)/Q. You also know that Cp-Cv for an ideal gas is equal to R. This should give you enough information to determine Cp.
 

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