How does refractive index matching make a solid disappear in a liquid?

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Refractive index matching causes a solid to appear invisible when submerged in a liquid by eliminating light distortion. When both the solid and the liquid share the same refractive index, light passes through them without scattering. This lack of scattering means that the solid does not disrupt the path of light, making it seem as if it is not present. The phenomenon relies on the electromagnetic properties of both materials being identical. Understanding this concept clarifies how objects can seemingly disappear in a medium.
baileya
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I'm just wondering how it works exactly? How can a solid submersed in a liquid somewhat "disappear". I've tried googling it with no luck and I'm super intrigued by this whole concept.

PS: the more clear and simple you can explain it, the better.. I tend to get confused easily by things like this.
 
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Reflection, refraction and diffraction rely on there being some kind of change in the material properties in the medium. If we immerse an object in some medium and both share the same primary electromagnetic properties then there will not be any distortion or pertubation to the electromagnetic waves. So if we place a homogeneous object into a fluid where both have the same index of refraction, then the light will pass through the fluid and the object without scattering. It's essentially invisible since the light behaves the same way as if the object wasn't there in the first place.
 
ohhh! that makes so much sense to me now :) thank you!
 
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