How does reverse bias affect leakage current in a diode?

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SUMMARY

The discussion focuses on the impact of reverse bias on leakage current in diodes, specifically addressing how minority charge carriers contribute to this phenomenon. When a diode is reverse biased, thermally generated electron-hole pairs are created, but the mobility of these carriers is significantly affected by the doping type. P-type doping introduces holes that recombine with electrons, while n-type doping results in an excess of electrons, leading to low mobility and limited current flow. Understanding these dynamics is crucial for analyzing diode behavior under reverse bias conditions.

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Danish_Khatri
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My question is related to the leakage current occurring in a diode when connected in reverse bias mode. When the diode is forward biased, the source voltage first neutralizes the barrier potential and then the flow of current occurs. However, I am not able to understand how the current due minority charges flow through a diode when it is reerse bias.
I would be very grateful if there is someone who can help me with this confusion.
 
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In reverse, electron-hole pairs are being thermally generated just as in the forward case. For every electron removed from its parent atom, a hole is generated as well. The electrons move when reverse biased, and they encounter holes due to p-type doping. The thermally generated electrons & holes are equal in number, but doping a semiconductor with p-type impurites, i.e. acceptors, results in low electron mobility. The electrons recombine with the abundant holes and few make it to the junction barrier. Likewise, on the n-side, an excess of electrons occur due to doping, and holes have low mobility.

It's all about mobility of e- & h+ which varies with doping level and whether the semiconductor material is n-type, p-type, or intrinsic.

Claude
 
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