How Does Smearing Charge dQ Uniformly on a Sphere Maintain Constant Energy?

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A uniformly charged sphere of radius r has charge Q distributed throughout its volume, and when an additional charge dQ is brought in from infinity and deposited uniformly on its surface, the potential energy is given by Q dQ/4πε₀r. The energy remains constant because the electric field E due to the total charge Q behaves as if it were concentrated at the center of the sphere, similar to a point charge. Smearing the charge dQ tangentially around the sphere does not affect the energy because it does not alter the radial distance from the center where the potential is calculated. This principle highlights the uniformity of the electric field around the sphere and its impact on energy calculations. Understanding this concept is crucial for first-year physics students studying electrostatics.
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A sphere of radius r contains a charge Q distributed uniformly throughout its volume. Charge dQ is brought in from infinity and deposited uniformly over the surface. The potential energy of the charge dQ is Q dQ/4\pi\epsilon<sub>0</sub>.

This follows naturally from the result for the potential of 2 point charges after noting
(a) E due to Q is the same as a point charge and
(b) smearing dQ around the sphere (i.e., tangential to the radial direction) doesn’t change the energy.

Why/how does "smearing dQ around the sphere (i.e., tangential to the radial direction) not change the energy"?

Thanks in advance for any help!

[N B : I am a first year physics undergraduate.]
 
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I am sorry for the poor latex code. The potential energy expression should read Q dQ/4\pi\epsilon_{0}
 
Mistaken for the second time now. The potential energy expression should read Q dQ/4\pi\epsilon_{0}r
 
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