How Does Snell's Law Affect Wavelength?

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Homework Help Overview

The discussion revolves around the application of Snell's Law in relation to the effect on wavelength when light passes through different media. Participants are exploring the relationship between refractive indices and wavelength changes, particularly in the context of white light and its constituent colors.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand how Snell's Law relates to wavelength changes and are questioning the coherence of different wavelengths in white light. There are discussions about the relevance of specific formulas and the nature of light emitted from a crystal.

Discussion Status

The discussion is ongoing, with participants providing insights and raising questions about coherence and the assumptions underlying the problem. Some guidance has been offered regarding the coherence of specific wavelengths, but no consensus has been reached on the overall interpretation of the problem.

Contextual Notes

There is mention of specific wavelengths associated with colors of light and the assumption that white light can be treated as a combination of these wavelengths. Participants are also considering the implications of coherence in the context of the problem.

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Homework Statement
With 2019 behind him, Rohan refracted on the past year by wearing his 2020-Hindsight- Fiber-Optic Glasses to view the magic coherent 2019 Crystal Ball. Unbeknownst to Rohan, the 2020 Glasses were defective because the left and right fibers of the glasses had different indices. Fiber Optic 1 had an index of refraction n1 = 1.5 and Fiber Optic 2 had index n2 = 2.5. Both fiber optic paths are exactly 339 cm in length. Bright white light, emitted by the very distant Magic Crystal Ball, enters each fiber of the glasses and travels along their radii until their images are superimposed on the single Screen of the glasses. What’s the most prominent color that Rohan sees in the image? Assume the fibers are very thin. Hint: 1 nm = 1×10-9 m.

(a) Red ( ≃ 647 nm)
(b) Yellow ( ≃ 575 nm)
(c) Green ( ≃ 516 nm)
(d) Blue ( ≃ 452 nm)
(e) White (all wavelengths)
Relevant Equations
There aren’t any relevant equations on the test
I thought about using the snell’s law because it involves different refractive index but I have no idea why the wavelength would be affected by the snell’s law. I thought that maybe if I found the frequency I might be able to get the wavelength but, I don’t know which formula I should use. I then tried to use the dispersion crystal, but I don’t know why I would do that.
 
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diggadigga said:
to view the magic coherent 2019 Crystal Ball.

Bright white light, emitted by the very distant Magic Crystal Ball, enters each fiber of the glasses and travels along their radii until their images are superimposed on the single Screen of the glasses.

Pretty goofy question. Can you say more about the apparent problem issue between the two parts of the problem statement that I've highlighted?
 
the magic coherent thing isn't related to the problem, the crystal just emits white light this image from the problem might help http://ibb.co/QC2LCym
 
diggadigga said:
the magic coherent thing isn't related to the problem
It is a strange problem, but it seems to me coherence is key.
I think you have to assume that for each wavelength emitted by the crystal ball it is emitted coherently; that is, the waves of a given wavelength enter the fibres in phase.
 
From my understanding white light is made from all of the visible light's wavelength, and since their wavelength is different they would never be coherent, is there a formula that you could give that would better explain this?
 
diggadigga said:
From my understanding white light is made from all of the visible light's wavelength, and since their wavelength is different they would never be coherent, is there a formula that you could give that would better explain this?
That's why I say it's a bit strange.
Note that they give you wavelengths of four specific colours, so assume this white light is made of just those four.
(And yes, it is possible to blend three or more pure wavelengths so that a human could not distinguish from white light as a continuous spectrum, so "white" does not imply a continuous spectrum.)
Each colour could in itself be coherent, and on that basis you can answer the problem.
 
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