How Does Switching a Magnetic Field Affect Coil Flux and Induced Current?

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SUMMARY

The discussion centers on the effects of switching a magnetic field on coil flux and induced current, specifically involving a coil with a radius of 4 cm and a magnetic field strength of 2 mT. When the magnetic field is switched off over 1 ms, a momentary current of 4 mA is observed. The change in magnetic flux through the coil when the field is turned off is calculated to be 0.01 Wb, and the rate of change of flux is derived from the induced electromotive force (emf) rather than the current itself.

PREREQUISITES
  • Understanding of Faraday's Law of Electromagnetic Induction
  • Familiarity with the concept of magnetic flux
  • Basic knowledge of coil geometry and area calculation
  • Ability to apply Ohm's Law in the context of induced current
NEXT STEPS
  • Study Faraday's Law and its applications in electromagnetic induction
  • Learn how to calculate magnetic flux for different coil configurations
  • Explore the relationship between induced emf and current in circuits
  • Investigate the effects of varying magnetic field strengths on induced current
USEFUL FOR

Physics students, electrical engineers, and anyone interested in the principles of electromagnetism and its applications in circuit design.

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Homework Statement


A coil of radious 4cm has its plane perpendictular to a uniform magnetic field of strenght 2 mT directed into the page as in the following diagram

http://i83.photobucket.com/albums/j283/cowsgomoo47/physics_prob_magnetism.jpg

The magnetic field is then switched off is such a way that it takes 1ms to drop to zero. When switched on again it also takes 1 ms. Switching off the field results in a momentary current of 4ma flowing through the milliameter from X to Y.

a) What is the change in magnetic flux through the coil when the field is turned off?

b) What is the rate of change of flux through the coil during this time?

Homework Equations





The Attempt at a Solution


a) \Phi=BA
=> ((3.14)x(4*10^-3))^2 x (2x10^-3)


b) I = \frac{change in magnetic flux}{change in time}
=> (4x10^-3) = (change in magnetic flux)/ (1x10^-3)
=4x10^-6
X WRONG
Right = 0.01 Wb <-- How??
 
Last edited by a moderator:
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The rate of change of magnetic flux doesn't give you the current. It gives you the induced emf.

You have found \triangle \Phi_B. You know what is \triangle t. See how to find the rate of change of flux?
 

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