How Does Temperature and Pressure Affect Balloon Volume?

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SUMMARY

The discussion focuses on the relationship between temperature, pressure, and volume of a balloon filled with air, utilizing the ideal gas law. The initial conditions are set at a volume of 1.15 L and a temperature of 296.5 K, with the pressure at standard temperature and pressure (STP) being 760 mm Hg at 273.15 K. The volume change when the balloon is taken outdoors to a temperature of 278.4 K and a pressure that is half of the initial pressure is calculated using the formula V2 = (P1V1T2) / (T1P2). The moles of gas remain constant throughout the process, which is crucial for determining the initial and final states of the gas.

PREREQUISITES
  • Understanding of the ideal gas law and its components (pressure, volume, temperature, moles)
  • Knowledge of standard temperature and pressure (STP) conditions
  • Familiarity with gas law calculations and conversions
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study the ideal gas law and its applications in real-world scenarios
  • Learn how to calculate changes in gas volume with varying temperature and pressure
  • Explore the concept of moles in gas calculations and their significance
  • Investigate the effects of altitude on atmospheric pressure and gas behavior
USEFUL FOR

This discussion is beneficial for students studying chemistry, physics enthusiasts, and anyone interested in understanding the principles of gas behavior under varying environmental conditions.

v3ra
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A balloon is filled up with air to a volume of 1.15 L at 296.5 K.* What does the volume change to if the balloon is taken outdoors where the temperature is 278.4 K and the pressure is half of what it was indoors?

V2 = (P1V1T2) / (T1P2)


How do I find the initial pressure at 296.5 K if I know that at STP the pressure is 760 mm Hg at 273.15 K?
 
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v3ra said:
A balloon is filled up with air to a volume of 1.15 L at 296.5 K.* What does the volume change to if the balloon is taken outdoors where the temperature is 278.4 K and the pressure is half of what it was indoors?

V2 = (P1V1T2) / (T1P2)


How do I find the initial pressure at 296.5 K if I know that at STP the pressure is 760 mm Hg at 273.15 K?

What remains constant in the process? Pressure, temperature, volume or moles?

If P is the initial pressure, what's the final pressure?
 
The moles would remain constant... how does this help me?
 
v3ra said:
The moles would remain constant... how does this help me?

Right! So what are the initial moles and final moles? Write the expressions. Do not evaluate.
 

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