How Does the Doppler Effect Alter Radar Frequencies?

In summary, the frequency at the target vehicle (f.tar) is equal to ((c-u)/c)*f.sou, the frequency of the reflected radiation (f.ref) at the radar gun is equal to (c/(c+u))*f.tar, and the simplified expression relating the initial frequency (f.sou) to the reflected frequency (f.ref) is f.ref = (c/(c+u))*((c-u)/c)*f.sou. However, this expression is incorrect as it does not account for the case when u=0, which would result in f.ref = f.sou.
  • #1
Lengalicious
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Homework Statement


Radar is used to measure the speed of passing vehicles. A stationary radar gun emits EM radiation, a proportion of which is reflected from the target vehicle which is moving away from the gun at 'u' ms^-1.

a)State the frequency at the target vehicle (f.tar) in terms of the frequency at the radar gun (f.sou).

The target vehicle then acts as a moving source emitting at frequency (f.tar), moving away from the radar gun.

b) State the frequency of the reflected radiation (f.ref) at the radar gun in terms of the frequency reflected by the target vehicle (f.tar).

c) Combine these expressions to relate the initial frequency (f.sou) to the reflected frequency (f.ref), simplifying the expression by assuming u<<c.


Homework Equations





The Attempt at a Solution



I say f.tar = ((c-u)/c)*f.sou
and f.ref = (c/(c+u))*f.tar

so, f.ref = (c/(c+u))*((c-u)/c)*f.sou

where f.ref = f.sou when u<<c. This surely can't be correct? What am i doing wrong?? Apparently there should be a beat frequency =S
 
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  • #2
Lengalicious said:
where f.ref = f.sou when u<<c. This surely can't be correct? What am i doing wrong?? Apparently there should be a beat frequency =S


Why is this incorrect? In the case that u=0, you would expect f.ref = f.sou. If there's no relative velocity there is no doppler shift.
 

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