How Does the Height of a Parachute Change with Horizontal Displacement?

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Homework Help Overview

The problem involves understanding how the height of a parachute, represented by the function h(x) = 50sin^-1(0.1x), changes with respect to horizontal displacement x from a landing target. The focus is on finding the rate of change of height with respect to displacement at a specific point.

Discussion Character

  • Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the need to find the derivative of the given function h(x) and question the original poster's understanding of derivatives, particularly the derivative of the arcsine function.

Discussion Status

Some participants have provided guidance on the derivative of the arcsine function and are prompting the original poster to apply this knowledge to the specific function in question. There is an ongoing exploration of the derivative related to the problem.

Contextual Notes

There is an expectation for the original poster to demonstrate some effort in solving the problem before receiving further guidance. The discussion also highlights the importance of understanding derivatives in the context of the problem.

JakePearson
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the height h(x) in meters above the ground of a parachute varies with her horizontal distplacement x in meters from a landing target on the ground as h(x) = 50sin^-1 (0.1x). what is the rate of change of h with respect to x at x = 6m?

i was wondering of someone could help me with this question :)
 
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Do you have any idea yourself? What are you thoughts on this problem? We require some effort from your side before we guide you to the answer.
 
Last edited:
What is the derivative of h(x) = 50sin^-1 (0.1x)? That's all this is asking. Do you know the derivative of arcsine?
 
is it
1 / sqrt(1-x^2)

:)
 
JakePearson said:
is it
1 / sqrt(1-x^2)

:)


yes so now you know

[tex]\frac{d}{dx} (sin^{-1}x)= \frac{1}{\sqrt{1-x^2}}[/tex]

what is d/dx( sin-1(0.1x)) ?
 

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