How Does the Limit Equal sqrt(e)?

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SUMMARY

The limit of the expression [1 + 1/(2x)]^x as x approaches negative infinity equals sqrt(e). This conclusion is derived using L'Hôpital's Rule, where the natural logarithm of y is evaluated, leading to the limit of ln(y) being 1/2. Consequently, the limit of y becomes e^(1/2), confirming that lim y equals sqrt(e). The discussion highlights the importance of recognizing the application of L'Hôpital's Rule in evaluating limits involving indeterminate forms.

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Homework Statement



Show that:

Lim [1+1/(2x)]^x = sqrt(e)
x->-inf

2. Homework Equations /theorums

l'hospital's rule

The Attempt at a Solution



Let y= [1+1/(2x)]^x

lny=ln [1+1/(2x)]^x

lny= x ln [1+1/(2x)]

Then
Ln Lim (y)=
x->-inf

Lim (lny)=
x->-inf

Lim x ln [1+1/(2x)]=
x->-inf

By l'hopital

and evaluating the resulting limit as x->-inf

I get 1/2.How does this limit equal the sqrt of "e"?
I know that it does, as i found a limit calculator online and sqrt(e) was the answer... but no matter how I try to do it, I can't get to sqrt"e".
 
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You found lim ln(y) is 1/2. What does that make lim y?
 
Last edited:
Oh...e^(1/2). Thank you very much! Although i feel a little dumb, the darn thing was staring me in the face. By the way thanks for the quick reply as well.
 

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