How Does the Radius of a Raindrop Affect Its Acceleration and Terminal Velocity?

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The discussion centers on the physics of a falling raindrop, specifically how its radius affects acceleration and terminal velocity. Participants agree that the acceleration due to gravity (g) is a fundamental factor, but emphasize the importance of drag, which is influenced by the raindrop's surface area. The terminal velocity is determined by the balance between gravitational force and drag, which varies with the raindrop's mass and radius. A special substitution for mass is necessary to solve the problem correctly, leading to the conclusion that the acceleration is g/7. Researching the "raindrop problem" is suggested for further insights into this classic physics challenge.
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So i have a problem with a question in which there is a falling raindrop where the mass and the radius are proportional and i have to find the acceleration with respect to radius and velocity.. I figured that bc it was falling its acceleration would be equal to g... but that seems to easy!
 
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the thing to be considered may be the drag of the drop as it falls down which depends on the surface area of the rain drop. this drag limits the velocity of the drop to a specific number...
 
This is a very old problem. Unfortunately, I remember the answer, g/7, but I don't remember how you get it. It has an unusual solution. There a special substitution that you need to make for the mass, otherwise the problem is insoluble. You might try to research "raindrop problem" with Google.
 
hollistb said:
So i have a problem with a question in which there is a falling raindrop where the mass and the radius are proportional and i have to find the acceleration with respect to radius and velocity.. I figured that bc it was falling its acceleration would be equal to g... but that seems to easy!

Sounds right to me, the only force accelerating a rain drop is due to gravity.

The terminal velocity however depends on the mass and radius.

http://en.wikipedia.org/wiki/Terminal_velocity

Maybe you're supposed to show the relationship between g (the rain drop's acceleration) and the terminal velocity of it.
 
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

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