How Does the Second Fragment's Velocity Change After a 2D Explosion?

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SUMMARY

The discussion focuses on calculating the velocity of the second fragment (B) after a 2D explosion involving a 4.00-kg cannonball that splits into two fragments. Fragment A, weighing 2.37 kg, moves at 19.7 m/s at an angle of 325º. By applying the conservation of momentum principle, the velocities of both fragments can be resolved into their x and y components to find the velocity of fragment B. The key takeaway is that the total momentum before and after the explosion remains constant, allowing for the calculation of the unknown fragment's velocity.

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  • Understanding of conservation of momentum in physics
  • Ability to resolve vectors into x and y components
  • Familiarity with basic kinematics equations
  • Knowledge of trigonometric functions for angle calculations
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  • Study vector resolution techniques in physics
  • Learn about conservation laws in explosive scenarios
  • Explore momentum calculations in two-dimensional motion
  • Practice problems involving explosions and fragment velocities
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Students studying physics, particularly those focusing on mechanics and momentum, as well as educators looking for examples of explosive motion scenarios.

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Homework Statement



A 4.00-kg cannon ball is flying at 18.5 m/s
[0º] when it explodes into two fragments.
One 2.37-kg fragment (A) goes off at
19.7 m/s [325º]. What will be the velocity of
the second fragment (B) immediately after
the explosion? Assume that no mass is lost
during the explosion, and that the motion
of the fragments lies in the xy plane.

Homework Equations



p = mv

The Attempt at a Solution



1564sir.jpg


K so i got my graph drawn, but because this is an explosion i have no idea how to set up the x and y equations, any help?
 
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You have to apply the conservation momentum. The explosion does not make any difference.
Resolve the momentum Pa and Pb along x and y axis. And proceed.
 

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