How Does the Singularity Behave as t Approaches 0 in the Kasner Solution?

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Homework Help Overview

The discussion revolves around the behavior of the singularity as time approaches zero in the context of the Kasner solution in general relativity. Participants explore the implications of the metric and the Einstein equations related to this solution.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the need to specify the form of the Kasner solution and the conditions on the exponents derived from Einstein's equations. There are attempts to understand the implications of substituting the metric into the equations and the behavior of the scale factors as time approaches zero. Questions arise regarding the positivity of the exponents and the nature of different Kasner solutions.

Discussion Status

The discussion is active, with participants providing insights into the relationships between the parameters of the Kasner solution and exploring various scenarios. Some guidance has been offered regarding the algebraic conditions that must be satisfied, and there is a recognition of the complexity of the behavior of the scale factors.

Contextual Notes

Participants note the constraints of the problem, including the requirement to describe the behavior of the singularity without deriving the Kasner solution itself. There is also mention of the potential errors in the source material being referenced.

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Homework Statement


Investigate the possible behaviour of the singularity as t \rightarrow 0 in the Kasner solution.


Homework Equations


The metric for the Kasner solution is given by

ds^2 = c^2dt^2 - X_1^2(t)dx_1^2 - X_2^2(t)dx_2^2 - X_3^2(t)dx_3^2


The Attempt at a Solution


I have no clue...
 
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Try writing down a more specific form of the Kasner soln. The spatial metric functions can be written as powers of t. What are the conditions on the exponents coming from Einsteins eqns?
 
I don't get it.
 
You can't do anything with the metric as written - it's too general. What ARE X_1,X_2 and X_3 in the Kasner soln. You may have to look it up...
 
All I can find about this is that substituting the metric into the Einstein equations gives

\frac{\ddot{X}_i}{X_i} - \left(\frac{\dot{X}_i}{X_i}\right)^2 +3\left(\frac{\dot{X}_i}{X_i}\right)\left(\frac{\dot{a}}{a}\right) = \frac{4\pi G}{c^4}\left(\rho - \frac{p}{c^2}\right)

in which a^3 = X_1X_2X_3.
 
That's a start. You shouldn't have a loose index i floating around though. Assuming you can get the correct Einstein equations (and there should be two), Kasner is a vacuum solution, so put rho=p=0. Put X_i=t^p_i. Turn this into equations in the constants p_i. Are you supposed to actually derive Kasner or just describe it's properties? It might be a good idea to just look up the solution to see what you are aiming for.
 
I think I'm just supposed to describe the behaviour of the singularity. I don't like this book, it has too many errors. ;) Why should I use X_i = t^{p_i}? According to my book this is a perfect fluid model.
 
Ok, I found that this is a particulary simple behaviour. Also

\frac{\dot{X}_1 \dot{X}_2}{X_1X_2} + \frac{\dot{X}_2 \dot{X}_3}{X_2X_3} + \frac{\dot{X}_3 \dot{X}_1}{X_3X_1} = \frac{8 \pi G}{c^4}\rho

Putting in X_i = t^{p_i} and using \rho=0 gives me

0 \propto \frac{1}{t^2}

Is this true?
 
It gives you an algebraic condition on the p's that must vanish. What is it? Again there is another Einstein equation. It will give you another algebraic condition.
 
  • #10
So p_1p_2 + p_2p_3 + p_3p_1 = 0?
I also got that

\frac{\dot{a}}{a} = \frac{1}{3} \left( \frac{\dot{X}_1}{X_1} + \frac{\dot{X}_2}{X_2} + \frac{\dot{X}_3}{X_3} \right)

but then I get some a aswell..?
 
  • #11
That is one alright. Since we are not actually trying to derive this you should find

p_1+p_2+p_3=1 and
{p_1}^2+{p_2}^2+{p_3}^2=1.
 
  • #12
Yeah that I got..
 
  • #13
Good. So there are actually lots of Kasner solutions corresponding to different values of the p's. Find a specific example and describe it's behavior.
 
  • #14
Well, what I don't understand is HOW to describe it's behaviour.
 
  • #15
Ok, here's a set of p's.

p_1=1/3, p_2=(1+\sqrt{3})/3, p_3=(1-\sqrt{3})/3

How would you describe this behavior as t->0?
 
  • #16
Well, I will always get

\frac{\dot{a}}{a} = \frac{1}{3t}

so for t \rightarrow 0

\dot{a} \rightarrow \infty
 
  • #17
Sure. But describe qualitatively the behavior of the scale factors themselves (the X_i's).
 
  • #18
Sorry, I don't know what to say about them.
 
  • #19
That's ok. In a matter dominated universe (a=t^(2/3), I think) a->0 as t->0. Is that true here?
 
  • #20
Humm, if I solve

\frac{\dot{a}}{a} = \frac{1}{3t}

I get

a = t^{1/3} \rightarrow 0

for t \rightarrow 0.

But if I use a_0 instead, I get

a = a_0 \frac{1}{3} ln(t) \rightarrow - \infty.
 
  • #21
You don't have to solve a DE for the scale factors. You already did that. a_i=t^p_i. Where the p_i's are what I sent you a few posts back. Note there are three different scale factors - the universe is anisotropic. And, hint, one of the scale factors is not like the others.
 
  • #22
I don't get it. What about t \rightarrow 0?
 
  • #23
And how do I get a_i = t^{p_i}?
 
  • #24
Logarythmic said:
And how do I get a_i = t^{p_i}?

Huh? It's a Kasner solution. The scale factors are t^p1, t^p2 and t^p3. I sent you a sample set of p's. What's the behavior of each as t->0?
 
  • #25
Well then every a_i \rightarrow 0 as for the matter dominated universe.
 
  • #26
Are all of the p's positive?
 
  • #27
No the third one is not. So this one behaves like \frac{1}{t} and thus goes to infinity. Right?
 
  • #28
Absolutely right. Two dimensions contract as t->0 and one expands. But this is only one of the many Kasner solutions. Are there any Kasner solutions where all p's are positive? Or are they all like this? I think this is the actual question you want to answer.
 
  • #29
Well wouldn't \vec{p} = [1,0,0] be a solution?
 
  • #30
Right again. One dimension expanding, two static. But can they all be positive (not zero)? Can two be negative and the third positive? I think once you've answered these you can say what the limiting behavior of the Kasner's are.
 

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