How does this system work? (Four pulleys and a rope lifting a mass)

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The discussion focuses on understanding a system of four pulleys and a rope used to lift a 40 N weight. Participants emphasize the importance of recognizing that tension remains constant throughout the rope, which is crucial for solving the problem. A free body diagram is suggested to clarify the forces acting on the pulleys. The purpose of multiple pulleys is to reduce the force needed to lift the weight by increasing the distance the hand moves compared to the load's movement. Overall, the conversation highlights the need for clear problem statements and proper application of physics principles in pulley systems.
zuzelle
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Homework Statement
The masses of pulleys are negligible. What is the value of force F that keeps the block of weight 40 N in balance?
Relevant Equations
This system confuses me a lot. Our teacher just summed up all the tension forces of vertical strings, got 5F = 40, but can we really do that? If tension is the same everywhere, why isn't F = 40? Because all these strings aren't attached to the block itself I think. Could someone please explain how do systems like this actually work?
I used the regular way of solving problems with pulleys. I tried to find the tension forces, which must be the same in the rope, but I get it wrong
 
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Hello @zuzelle ,
:welcome: ##\qquad##!​

zuzelle said:
Homework Statement:: The masses of pulleys are negligible. What is the value of force F that keeps the block of weight 40 N in balance?
Relevant Equations:: This system ...

WHAT system ? Are we suposed to be telepathic ? Do you want us to guess ?

Please read and follow the PF guidelines

And show your work

##\ ##
 
If tension is the same everywhere
So apparently it is not. Can you see why ?
[edit] hint: a free body diagram for the bottom pulley wheel ? For the top one ?

##\ ##
 
Welcome @zuzelle !

The whole reason for using so many pulleys is to reduce the force needed to be applied at the end of the rope, which happens to be the value of the tension for any section of the going-around rope.

Just like it happens for a typical lever, that reduction of applied force is achieved by increasing the distance that the hand has to move respect to the distance the load moves upwards.

What you see in that diagram is basically a group of (rotating) levers simultaneously working.
 
zuzelle said:
Our teacher just summed up all the tension forces of vertical strings, got 5F = 40,
Not exactly. Your teacher summed the five forces that the string wrapped around the pulleys exert on the lower pulley assembly. That excludes the string attached to the ceiling and the string attached to the weight.
Since it is all the same massless string, and can freely rotate the pulleys, the tension must be the same in each section.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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