How Does Throwing a Snowball Affect an Ice Skater's Movement?

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SUMMARY

The discussion centers on a physics problem involving a 60 kg ice skater who throws a 12 kg snowball with a velocity of 3.0i + 4.0j m/s. The key concept is the conservation of momentum, expressed as p = mv. The correct approach involves calculating the skater's subsequent velocity after the snowball is thrown, using the momentum equation m1v1 = m2v2. The final velocity of the skater is determined to be 5 m/s in the opposite direction of the snowball's throw.

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Homework Statement


A 60Kg ice skater, at rest on frictionaless lce, tosses a 12kg snowball with velocity given by v= 3.0i + 4.0j m/s, where the x and y axes are both in the horizontal plane. What is the subsequent belocity of the skater?


Homework Equations



p=mv

The Attempt at a Solution



I thought this was a momentum problem where I had to convert the velocity out of i + j form. I think it is 5 m/s.

I tried m1v1=m2v2 but i am not sure if that is right...
 
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MBURNS001 said:
I tried m1v1=m2v2 but i am not sure if that is right...

It might be. What are m1, m2, v1, and v2?
 

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