How Does Torque Affect the Acceleration of a Stick's Tip?

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SUMMARY

The discussion focuses on calculating the acceleration at the tip of a stick when torque is applied, ignoring gravity. The key equations include the moment of inertia I = mL²/3, angular velocity ω = -dθ/dt, and the resulting accelerations: centripetal acceleration ac = rω² and tangential acceleration at = τL/I = 3τ/mL. The overall acceleration a is expressed as a = ac + at, with specific components ax and ay derived from the applied torque and angular motion.

PREREQUISITES
  • Understanding of angular motion and torque
  • Familiarity with moment of inertia calculations
  • Knowledge of polar and Cartesian coordinate systems
  • Basic principles of rotational dynamics
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Physics students, mechanical engineers, and anyone interested in the dynamics of rotating bodies and torque applications.

  • #31
LogicalTime said:
my final result for the acceleration is:
<br /> a_{r} = r\dot{ \theta}^2-g \cos( \theta)<br />
<br /> a_{\theta} = r \ddot{ \theta } - g \sin( \theta)<br />

where
<br /> \ddot{\theta} = \frac{\tau}{I}<br />[/QUOTE

at least the units match up now lol
 
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  • #32
If you did not put mg as part of the net torque, how do you cancel out the normal force from the hinge?
 

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