How Does Torque Affect the Acceleration of a Stick's Tip?

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LogicalTime said:
my final result for the acceleration is:
[itex] a_{r} = r\dot{ \theta}^2-g \cos( \theta)[/itex]
[itex] a_{\theta} = r \ddot{ \theta } - g \sin( \theta)[/itex]

where
[itex] \ddot{\theta} = \frac{\tau}{I}[/itex][/QUOTE

at least the units match up now lol
 
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If you did not put mg as part of the net torque, how do you cancel out the normal force from the hinge?