LogicalTime
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LogicalTime said:my final result for the acceleration is:
[itex] a_{r} = r\dot{ \theta}^2-g \cos( \theta)[/itex]
[itex] a_{\theta} = r \ddot{ \theta } - g \sin( \theta)[/itex]
where
[itex] \ddot{\theta} = \frac{\tau}{I}[/itex][/QUOTE
at least the units match up now lol