How Does Torque Affect the Acceleration of a Stick's Tip?

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LogicalTime said:
my final result for the acceleration is:
[itex] a_{r} = r\dot{ \theta}^2-g \cos( \theta)[/itex]
[itex] a_{\theta} = r \ddot{ \theta } - g \sin( \theta)[/itex]

where
[itex] \ddot{\theta} = \frac{\tau}{I}[/itex][/QUOTE

at least the units match up now lol
 
If you did not put mg as part of the net torque, how do you cancel out the normal force from the hinge?