How does Total Internal Reflection in a mm/sm fiber work?

In summary, the conversation discusses the principles of fiber optics, specifically the behavior of single and multimode fibers in relation to total internal reflection. The effectiveness of total internal reflection in carrying light depends on the mode order, which is determined by the fiber's material properties and diameter. Higher order modes are more likely to escape when the fiber bends, and the maximum mode order that can be sustained varies. A helpful resource on waveguides is also mentioned.
  • #1
TinaTina
7
0
I know Snell's Law and I do understand that there are single and multimode fibers. A fiber carries light hence to total internal reflection. so far so good. But is it only a single mode fibre that works with total internal reflection? And if so, how does the multimode fibre carry light then?
 
Science news on Phys.org
  • #2
Here is what I understand about the general principles of fiber optics. I am no expert on the engineering aspect of them or properties of specific commercially available products.

We're talking wave-guides here and for the higher order modes the effective angle at which the plane waves (or photons if you wish) impinge upon the fiber walls is greater. (until you have 90deg to the wall for standing waves). Thus higher modes will be reflected less and escape more readily when the fiber bends. Whether you are modeling fibers as internally reflecting or whether there is axially focusing refraction due to radial difference in index of refraction this should be the same issue with higher modes. Above some order, the fiber just can't retain that mode of the light at that frequency. How high a mode order can be sustained would be a function of the fiber's material properties and diameter and I imagine that need not exclude several of the lowest order modes in some cases.
 
  • Like
Likes TinaTina
  • #4
Thank you, jambaugh. That was helpful!
 

1. What is Total Internal Reflection (TIR) in a mm/sm fiber?

Total Internal Reflection is a phenomenon that occurs when a light ray travels from a denser medium to a less dense medium, such as from glass to air. The light ray hits the boundary between the two media at an angle greater than the critical angle, causing it to be completely reflected back into the denser medium. This results in the light being trapped and allowing it to travel through the fiber with minimal loss.

2. How does TIR work in a mm/sm fiber?

In a mm/sm fiber, TIR works by using a core layer of high refractive index material surrounded by a cladding layer of lower refractive index material. When a light ray enters the fiber at an angle greater than the critical angle, it is reflected back into the core layer, where it continues to bounce off the boundaries due to the difference in refractive index. This results in the light being confined within the core and traveling through the fiber with minimal loss.

3. What factors affect TIR in a mm/sm fiber?

The critical angle for TIR in a mm/sm fiber is determined by the difference in refractive index between the core and cladding layers. This difference is influenced by the materials used, the geometry of the fiber, and the wavelength of the light. Additionally, the quality of the fiber, including its smoothness and cleanliness, can also affect the efficiency of TIR.

4. What are the applications of TIR in mm/sm fibers?

TIR in mm/sm fibers is primarily used in telecommunications and data transmission. It allows for the efficient transmission of data through long distances with minimal loss of signal. TIR is also utilized in medical imaging, such as endoscopes, and in fiber optic sensors for various industries.

5. Are there any limitations to TIR in mm/sm fibers?

While TIR is a highly efficient method of transmitting light through fibers, there are some limitations to be aware of. For TIR to occur, the angle of incidence must be greater than the critical angle, meaning that light must enter the fiber at a specific angle. Any deviation from this angle, such as bending or twisting of the fiber, can cause losses. Additionally, TIR is only effective for a certain range of wavelengths, so fibers must be carefully designed for specific applications.

Similar threads

Replies
2
Views
2K
Replies
22
Views
2K
Replies
1
Views
627
Replies
4
Views
4K
Replies
14
Views
3K
Replies
7
Views
2K
Replies
4
Views
1K
  • Classical Physics
2
Replies
37
Views
2K
Replies
4
Views
689
Replies
1
Views
782
Back
Top