The discussion centers on calculating the torque about the pivot point S in a seesaw and spring system. The user initially calculates the torque from the plate's weight and the spring force but overlooks the impact of using ##m## instead of the correct mass ##M = 2m## for the disk. It is clarified that the weight of the rod does not contribute to torque since it acts directly on the pivot. The confusion arises from the incorrect mass assumption, which affects the overall torque calculation. Accurate mass representation is crucial for determining the system's behavior.
The question ask to find torque about the pivot point S.
I first find the torque due to gravity of the plate and then torque due to spring force.
I understand that the weight of the rod do no torque as it is acting on the pivot S.
Where have I gone wrong?
Kindly see the attached pdf. My attempt to solve it, is in it.
I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction.
I'm not able to figure out, why my solution is wrong, if it is wrong .
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h.
So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance)
My thoughts for the first case , one of them must be 12 volt while the other is 0
The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...