How Does WolframAlpha Calculate the Sum of (2n+1)/(n(n+1)(n+2))?

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SUMMARY

The discussion centers on the calculation of the infinite sum of the series (2n+1)/(n(n+1)(n+2)) from n=1 to infinity, which WolframAlpha evaluates to 5/4. Participants emphasize the importance of deriving the partial sum formula to understand how this result is achieved. The conversation highlights the need for a clear method to derive the partial sum formula, which is essential for reaching the final result. Users express difficulty in obtaining this formula, indicating a gap in understanding the underlying mathematical principles.

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antarctic
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Did you try to get the derivation of the partial sum formula? Once you have that the final result is obvious.
 
Thank you very much for the quick answer, but:

mathman said:
Did you try to get the derivation of the partial sum formula? Once you have that the final result is obvious.

how do you get the partial sum formula? I can't seem to get that
 

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