How Efficient Can a Radiative Heat Engine Be for a Moon Base?

Click For Summary
SUMMARY

The maximum theoretical efficiency of a radiative heat engine designed for a Moon base, utilizing sunlight, is calculated to be 95% based on the temperature ratio derived from Wien's law. The surface temperature of the Sun is approximately 6000 K, while the Moon's surface temperature is around 300 K. However, achieving this efficiency in practice is impractical without the use of optical systems to focus sunlight, as the Moon's surface will only reach temperatures close to its own due to the limited angle of sunlight received. The discussion emphasizes the necessity of additional equipment, such as lenses, to increase the temperature of materials to around 1000 K for effective heat engine operation.

PREREQUISITES
  • Understanding of Wien's Law and its application in thermal radiation
  • Knowledge of thermodynamic efficiency calculations
  • Familiarity with the concept of blackbody radiation
  • Basic principles of optical systems and lens focusing
NEXT STEPS
  • Research Wien's Law and its implications for thermal systems
  • Study thermodynamic efficiency and its calculations in heat engines
  • Explore blackbody radiation and its relevance to celestial bodies
  • Investigate the design and application of optical systems for energy concentration
USEFUL FOR

Engineers, physicists, and researchers interested in renewable energy systems, particularly those focused on extraterrestrial applications and the design of efficient heat engines for lunar environments.

Physgeek64
Messages
245
Reaction score
11

Homework Statement


The emission of radiation from the Sun’s disc is observed to peak at 0.5 μm wave- length and that from the Moon’s disc at 10.0μm. A heat engine to power a Moon base is to be constructed using radiation collected from the Sun. What is the maximum theoretical efficiency of such an engine? Comment on whether it would be practical to achieve this.

Homework Equations

The Attempt at a Solution


##T\lambda_{max}=constant##
##T_{moon}\lambda_{moon max}=T_{sun}\lambda_{sun max}##
##\frac{T_{moon}}{T_{sun}}=0.05##

##\eta=1-\frac{Q_2}{Q_2}##
##\frac{Q_2}{Q_1}=\frac{T_2}{T_1}##
##\eta=1-0.05=0.95##

does this seem right? I feel like assuming the radiation is the same temperature as the sun is wrong

but i don't know how to relate this all together. Any help would be greatly appreciated. Many thanks
 
Last edited:
Physics news on Phys.org
I believe you computed it correctly. One item of interest is the constant in the Wien's law formula is ## 2898 \, \mu m \, K ## making the temperature of the (surface of the} sun ## T_{sun} \approx 6000 \, K ## , and that of the moon ## T_{moon} \approx 300 \, K ##. ## \\ ## Note: The question also asks to comment on whether this is practical. To answer this question really requires some additional background material, so let me provide some of that info: ## \\ ## In order for light from the sun to be able to heat an object up to ## T ## anywhere near ## 6000 ## K , you would need to use lenses to focus the light onto the surface, (with the surface in the focal plane of the lens), and the lens system would need to fill a good portion of the hemisphere surrounding the surface being heated. Is this practical? ## \\ ## Without the use of optics, the sun only subtends an angle of ## \Delta \theta=.01 ## radians, (as seen from the Earth or moon), and would basically heat up surfaces that are placed on the moon to the same temperature as the surface of the moon. (That's why the moon is at the temperature that it is. The moon's surface, (assuming emissivity 1.0, but this same dynamic equilibrium also holds for a greybody), is radiating away energy as a blackbody at temperature ## T_{moon} ##, at the same rate that it is receiving energy from the sun). ## \\ ## Additional question: Would it perhaps be somewhat more practical to use lenses to make a heat engine system where (smaller) lenses heated the material to a temperature in the neighborhood of ## T= 1000 \, K ## ?
 
Last edited:

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
1K
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 6 ·
Replies
6
Views
11K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K