A boulder rolls down a hill with a constant acceleration of 3.69 m/s² for a duration of 7.72 seconds, resulting in a calculated distance of 91.64 meters. The correct formula used is d = v0 * t + 0.5 * a * t², where initial velocity (v0) is zero. Misinterpretations regarding the acceleration value and time duration were clarified, emphasizing the importance of using the given parameters directly from the problem statement.
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Doraneli said:1. A boulder initially at rest rolls down a hill with an acceleration of 3.69m/s^2. If it accelerates for 7.72 seconds, how far will it move?
2. d=v0(initial velocity)t+.5at^2
3. d=(0)(7.72)+.5(-9.8)(3.27)^2
Where did the "-39.24" come from? And why the "+-" for the second term?-39.24+-52.4
-91.64m