How Far Does a Golf Ball Travel When Struck at 30 Degrees?

AI Thread Summary
A golf ball struck at a 30-degree angle with an initial velocity of 11 m/s travels a horizontal distance of approximately 10.9 meters and reaches a maximum height of about 1.54 meters. To achieve a distance of 100 meters with the same trajectory, the required initial velocity would need to be around 33.7 m/s. The calculations utilize the equations for projectile motion, specifically focusing on the vertical and horizontal components of the ball's trajectory. The responses indicate that the initial results are correct, although the distance traveled suggests the golfer may lack skill. The discussion emphasizes the application of physics principles in analyzing projectile motion.
bobmarly12345
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Homework Statement


a golf ball is struck at an angle of 30 degree with respect to the horizontal, at a velocity of 11m/sec. the golf course is perfectly level and the golf ball stops instantaneously when it hits the ground.
a) determine the horizontal distance traveled by the golf ball
b) determine the maximum height attained by the golf ball
c) if the golf ball is to travel a distance of 100m using the same initial trajectory, determine the required initial velocity

Homework Equations


(u²sin2theta)/g
(u²sin²theta)/2g
sqrt((rg)/sin2theta)



The Attempt at a Solution


vertical component = 11sin30
horizontal " = 11cos30

a) range = [11²xsin(2x30)]/9.81 = 10.9m
b) height = [(11²xsin(30)²)/2x9.81 = 1.54m
c) 100m/s
sqrt((100.9.81)/sin(2x30))=33.7m/s

thats what I've done, i think its right but would like it if someone could check if I'm doing it right? whoever is hitting this golf ball doesn't seem very good if they're hitting it 10.9m :)
cheers
 
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Your results look fine.
 
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