How far will it slide before stopping?

[sweet_calyn04]

1. A 400g Block with an initial speed of 80cm/s slides a long a horizontal tabletop against a frictional force of 0.80N.
A) How far will it slide before stopping?
B) What is the coefficient of friction between the block and the tabletop?



2. A 50kg block rests at the top of a smooth plane whose length is 2.0m and whose length is 2.0m and whose length is 0.5m. How long will it take for the block to slide to the bottom of the plane when released?



3. A 6.0lb block rest on a smooth plane inclined at an angle of 20 with the horizontal. The block is pulled up the plane with a force of 30lb parallel to the plane. What is its acceleration?



4. A 2.0 Ton elevator is supported by a cable that can safely support 6400lb. What is the shortest distance in which the elevator can be brought to a stop when it is descending with a speed of 4.0ft/s?



5. A 50kg block is placed a smooth tabletop. A horizontal card attached to the block passes over a light frictioness pulley and is attached to 4.0kg body. Find the acceleation and the tension in the card when the system is released?




6. Two boddies having masses M1=30g and M2= 40g are attached to the ends of a string of negligible mass and suspended from a frictionless pulley. Find the acceleration of the bodies and the tension in the string?




7. Consider the object on a horizontal frictioness plane, acted upon by a single horizontal force.
A) If the mass is 1g and the force is 1dyne, the acceleration is ______?
B) If the mass is 1g and the force is 5dyne the acceleration is________?
C) If the weight is 32lb and the force is 1lb the acceleration is________?
D) If the weight is 320lb and the force is 20lb the acceleration is______?
E) If the mass is 6.0kg and the force is 20N the acceleration is________?
f) If the mass is 1.0K and the force is 9.8N THE ACCELERATION IS ______?

 

[CompuChip]

Hm, interesting questions.
I see preciously little filled out under the last two points ("relevant equations" and "the attempt at a solution") however. Surely, you must have some ideas?

 

[baba89]

A) To determine how far the 400g block will slide before stopping, we can use the equation for distance (d = v^2/2a), where v is the initial speed and a is the acceleration. In this case, the acceleration is equal to the net force divided by the mass (a = F/m). The net force in this scenario is the frictional force (F = 0.80N), so the acceleration would be 0.80N/0.4kg = 2m/s^2. Plugging this into the distance equation, we get d = (0.8m/s)^2/2(2m/s^2) = 0.2m. Therefore, the block will slide 0.2m before stopping.

B) The coefficient of friction can be calculated using the equation F = μN, where μ is the coefficient of friction, N is the normal force, and F is the frictional force. In this scenario, the normal force is equal to the weight of the block (N = mg). Plugging in the values, we get 0.80N = μ(0.4kg)(9.8m/s^2). Solving for μ, we get a coefficient of friction of μ = 0.20.

2. To determine how long it will take for the 50kg block to slide to the bottom of the plane, we can use the equation for distance (d = 1/2at^2), where a is the acceleration. The acceleration in this case is equal to the component of the gravitational force parallel to the plane (a = mgsinθ). Plugging in the values, we get d = 1/2(50kg)(9.8m/s^2)sin(0.5m/2.0m) = 1.2m. Therefore, it will take approximately 1.2 seconds for the block to slide to the bottom of the plane.

3. The acceleration of the 6.0lb block can be calculated using Newton's second law (F = ma), where F is the net force and a is the acceleration. In this scenario, the net force is equal to the applied force minus the component of the gravitational force parallel to the plane (F = 30lb - 6.0lb*sin20). Plugging in the values, we get a = (30lb -