How Fast Does a Rock Accelerate Past a Window?

  • Thread starter Thread starter mgerman63016
  • Start date Start date
  • Tags Tags
    Rock Window
Click For Summary

Homework Help Overview

The problem involves a rock being dropped from a building and passing a window, with specific questions about its velocity, time, and distance related to the window. The subject area pertains to kinematics and uniformly accelerated motion under gravity.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the velocity of the rock as it passes the window using a basic equation for unaccelerated motion. Some participants question the appropriateness of this approach given the rock's acceleration due to gravity. Others suggest considering different equations for uniformly accelerated motion.

Discussion Status

The discussion is ongoing, with participants exploring various equations related to uniformly accelerated motion. Guidance has been offered regarding the need for a different approach, but no consensus has been reached on the specific equations to use.

Contextual Notes

Participants are working with the constraints of the problem as presented, including specific values for height and time, while also grappling with the implications of acceleration on their calculations.

mgerman63016
Messages
12
Reaction score
0
1. A rock is dropped off the top of a building. On the way down, the rock passes a window. The window is known to be tall and the stone takes 0.154 to fall past the window.

1. What is the velocity of the rock at the bottom of the window?
2. How much time was necessary from the instant the rock was dropped until it reached the top of the window?
3. How far above the top of the window was the rock dropped?


So far I got
Yi=2.00m
Vi=?
a=9.81m/s^2
t= 0.154s
Yf= 0m
Vf=0m/s
I also got the initial velocity for the top window to be 12.98m/s which because I got my estimation wrong I got the answer wrong...sigh...BUT if I can get a little guidance I would GREATLY appreciate it! THANKS

And for my equation I used V = Δx/Δt = 2.00/0.154 = 12.98 m/s
 
Physics news on Phys.org
The equation you used is good for an unaccelerated motion. The rock's is accelerated. What equations should you use for it?
 
could i use the

2a(y-yi)=Vy2-Voy2??
 
This equation alone will not do it. What is the basic equation of uniformly accelerated motion?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
Replies
10
Views
5K
Replies
8
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
3
Views
26K
  • · Replies 36 ·
2
Replies
36
Views
3K
  • · Replies 4 ·
Replies
4
Views
8K
  • · Replies 7 ·
Replies
7
Views
4K