How Fast Does the Tip and Center of Mass of a Falling Rod Travel?

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SUMMARY

The discussion focuses on the dynamics of a falling rod, specifically a long, thin rod with a mass of 9.65 kg and a length of 10.18 cm. When the rod falls, the angular velocity (ω) is calculated to be 17 rad/sec. The linear velocity of the tip of the rod upon impact with the table is determined to be 1.73 m/s, while the speed of the center of mass is calculated to be 0.865 m/s. The relationship between the velocities of the tip and the center of mass is confirmed, demonstrating that the linear velocity for the center of mass is consistently half that of the tip in this scenario.

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sweetpete28
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A long, thin rod of mass 9.65 kg and length 10.18 cm is standing stright up on a table. Its lower end rotates on a frictionless pivot. A very slight push causes the rod to fall over.

What is the speed of the tip of the rod as it hits table?

What is speed of center of mass of rod?

1/2 m g L = 1/2 x 1/3 m L^2 ω^2


ω= 17 rad/sec

linear velocity = ω L =17 rad/s x 0.102m = 1.73m/s (tip of rod)

For speed of center of mass should I just multiply ω by L/2 (.0509m)...? Yes...right? I get .865 m/s which is half the linear velocity at tip...is linear velocity for center of mass always half of velocity at tip for situation like this?
 
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I haven't checked your math, but recall that v =ωr. Since ω is the same for all points on the rod, it follows that v scales linearly with distance from the centre of rotation.
 

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