How Fast is the Motorcycle in This Doppler Effect Scenario?

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TheRedDevil18
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Homework Statement



A hooter on a motorcycle sounds a note of 6000Hz when the motorcycle is stationary. You detect a shift in frequency of 30Hz when the motorcycle approaches you and then recedes from you. Calculate the speed of the motorcycle.
Speed of sound = 340m/s

Homework Equations



fl = fs(v/v-vs)

The Attempt at a Solution



When motorcycle approaches:

fl = (v/v-vs)
6030 = (340/340-vs)
vs = 16.58m/s

When motorcycle recedes:

fl = (v/v+vs)
5070 = (340/340+vs)
vs = 54.48m/s

Is this correct?
 
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I believe that the problem intends that the motorcycle moves towards you, then passes you by, always moving at the same speed. 30 Hz is the difference between those two frequencies.
 
So fl-fl prime = 30Hz ? , so if I set up two equations, fl = fs(v/v-vs) and fl prime = fs(v/v+vs) and then subtract them and equate to 30 and solve for vs, will that be right?
 
TheRedDevil18 said:
So fl-fl prime = 30Hz ? , so if I set up two equations, fl = fs(v/v-vs) and fl prime = fs(v/v+vs) and then subtract them and equate to 30 and solve for vs, will that be right?
Sounds good to me.
 
6000(340/340-vs) - 6000(340/340+vs) = 30
Is that how I would set up the equation?
 
TheRedDevil18 said:
6000(340/340-vs) - 6000(340/340+vs) = 30
Is that how I would set up the equation?
Yes, exactly.
 
Speed of the motorcycle worked out to be 0.85m/s, correct?
 
TheRedDevil18 said:
Speed of the motorcycle worked out to be 0.85m/s, correct?
Looks good to me.
 
Ok, thanks Doc Al