How Fast is the Shadow Length Changing as the Woman Walks?

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SUMMARY

The discussion centers on a related rates problem involving a street light and a woman walking away from it. The pole height is 18 feet, and the woman is 6 feet tall, walking at 4 ft/sec. The key equation derived is based on similar triangles, leading to the relationship between the shadow length and the distance from the pole. The final calculation for the rate of change of the shadow length, denoted as c', is found to be 420/111 ft/sec, although the solution is questioned for accuracy.

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Chas3down
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Homework Statement


A street light is at the top of a pole that is 18 feet tall. A woman 6 ft tall walks away from the pole with a speed of 4 ft/sec along a straight path. How fast is the length of her shadow moving when she is 35 ft from the base of the pole?

Homework Equations



a^2 + b^2 = c^2
b' = 4

The Attempt at a Solution



18/6 relate to
x/(x-35)

I got x = 35/2

so total length of side is 105/2

18^2 + 105/2 ^ 2 = 111/2 ^ 2

2aa' + 2bb' = 2cc'

a' = 0, height of pole never changes

2*35*4 = 111/2 * c'

c' = 420/111

but wrong anwser
 
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Chas3down said:

Homework Statement


A street light is at the top of a pole that is 18 feet tall. A woman 6 ft tall walks away from the pole with a speed of 4 ft/sec along a straight path. How fast is the length of her shadow moving when she is 35 ft from the base of the pole?


Homework Equations



a^2 + b^2 = c^2
b' = 4


The Attempt at a Solution



18/6 relate to
x/(x-35)

I got x = 35/2

so total length of side is 105/2

18^2 + 105/2 ^ 2 = 111/2 ^ 2

2aa' + 2bb' = 2cc'

a' = 0, height of pole never changes

2*35*4 = 111/2 * c'

c' = 420/111

but wrong anwser

You should at least explain what your variables mean. Could you do that?
 
Are you looking for the rate at which the shadow is moving relative to the person or relative to the base of the light pole ?
 

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