How Fast Is the Shadow's Height Changing as the Dog Approaches the Wall?

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SUMMARY

The discussion focuses on a related rates problem involving a dog running towards a wall while casting a shadow. The dog, 0.5m tall, runs at a speed of 1 m/s towards a wall located 14m away. The key equations utilized include the Pythagorean theorem and principles of similar triangles to determine how fast the height of the dog's shadow on the wall is decreasing when the dog is 5 meters from the wall. The final calculation reveals that the rate of change of the shadow's height is 9/32 m/s.

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  • Understanding of related rates in calculus
  • Familiarity with the Pythagorean theorem
  • Knowledge of similar triangles
  • Basic differentiation techniques
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  • Explore applications of the Pythagorean theorem in real-world scenarios
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Homework Statement


A spotlight on the ground shines on a wall 14m away. If a dog, 0.5m tall, runs from the spotlight towars the building at a speed of 1 m/s, how fast is the height of the animal's shadow on the building decreasing when the dog is 5 meters from the building?

Wrt = with respect to

Homework Equations


Pythagoreon theorem, implicit differentiation, you name it.


The Attempt at a Solution



Knowing that Dc/dt is canine wrt time is 1 m/s and i am trying to find dh/dt 'h' for height wrt time

and I am stuck...
.
..
...
14^2 + wall^2 = Hyp^2
 
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This is called a "related rates" problem, not "implicit differentiation."

dc/dt? if you're using the pythagorean theorem, that implies (at least to me) that the dog is running on the hypotenuse??

At a glance, I'm having a tough time getting the pythagorean theorem to really work for me on this problem. Have you thought about the angle made by the flashlight between the ground and the beam to the top of the dog? Or, have you thought about similar triangles?
 
You should have put "similar triangles", not "Pythagorean theorem", in "Relevant Equations". Can you draw a picture and see why?
 
Here i go furthering my development in related rates
let l be length of shadow and let x be ground covered with light
2/L = X/12
24=LX
L=24X^-1
dL/dt(1)=-24X^-2
dL/dt=-24(12-8)^-2
dL/dt=9/32
 

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