How Fast Must a Flywheel Rotate to Store 1.4 x 10^9 J?

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Homework Help Overview

The discussion revolves around calculating the rotational speed required for a flywheel to store a specific amount of energy, specifically 1.4 x 10^9 J. The context involves the principles of rotational kinetic energy and its application in energy storage systems, such as in electric vehicles.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for kinetic energy related to a flywheel and express uncertainty about how to apply it to find the necessary rotational speed. There are questions about the definition of angular velocity (ω) and the interpretation of variables within the equations.

Discussion Status

Some participants have attempted calculations based on the kinetic energy formula, providing values for mass, radius, and energy. There is an ongoing exploration of how to correctly derive the angular velocity and convert it to the desired units of revolutions per minute. Guidance has been offered regarding the importance of unit conversion.

Contextual Notes

Participants are working under the constraints of a homework problem, which may limit the information available for assumptions or additional context. There is a focus on ensuring the correct application of formulas and units in the calculations.

mikefitz
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A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk and its center. Rotating flywheels provide a means for storing energy in the form of rotational kinetic energy and are being considered as a possible alternative to batteries in electric cars. The gasoline burned in a 387-mile trip in a typical midsize car produces about 1.4 x10^9 J of energy. How fast would a 16-kg flywheel with a radius of 0.22 m have to rotate in order to store this much energy? Give your answer in rev/min.

I know the kinetic energy of a flywheel is: http://content.answers.com/main/content/wp/en/math/1/4/8/148da762c81d0061d84cb36a21fb1e4e.png but how do I use that information to calculate how fast the flywheel needs to rotate? Thanks
 
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mikefitz said:
A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk and its center. Rotating flywheels provide a means for storing energy in the form of rotational kinetic energy and are being considered as a possible alternative to batteries in electric cars. The gasoline burned in a 387-mile trip in a typical midsize car produces about 1.4 x10^9 J of energy. How fast would a 16-kg flywheel with a radius of 0.22 m have to rotate in order to store this much energy? Give your answer in rev/min.

I know the kinetic energy of a flywheel is: http://content.answers.com/main/content/wp/en/math/1/4/8/148da762c81d0061d84cb36a21fb1e4e.png but how do I use that information to calculate how fast the flywheel needs to rotate? Thanks
What is the definition of ω?
 
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Rearrange your equation to solve for omega. Do you know what each variable in that equation represents?
 
E=1.4*10^9 J
m=16kg
r=.22m

I=.5*16kg*.22^2 = .3872

1.4*10^9=.5*.3872*w^2

w=85037.67 rev/min?
 
mikefitz said:
E=1.4*10^9 J
m=16kg
r=.22m

I=.5*16kg*.22^2 = .3872

1.4*10^9=.5*.3872*w^2

w=85037.67 rev/min?
ω is in radians/second. If you had included the units in your calculation, you would have found the answer to have units of 1/s. The radians are a dimensionless quantity we add to the result because we know they were used in deriving the kinematic equations or rotation. You need to convert radians per second to revolutions per minute.
 

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