How Fast Must a Plane Fly to Overcome Wind from London to Rome?

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SUMMARY

The discussion focuses on calculating the required velocity of a plane flying from London to Rome, a distance of 1400 km at an angle of 42° East of South, while overcoming a 75 km/hr eastward wind. Participants emphasize the need to construct a vector triangle to represent the velocities involved. The triangle should include the wind's velocity, the plane's ground velocity, and the unknown airspeed of the plane. Using trigonometric laws, specifically the sine and cosine laws, will yield the necessary calculations.

PREREQUISITES
  • Understanding of vector addition in physics
  • Knowledge of trigonometric functions (sine, cosine, tangent)
  • Familiarity with the cosine and sine laws
  • Basic principles of relative velocity
NEXT STEPS
  • Study vector addition and resolution of forces in physics
  • Learn the sine and cosine laws in triangle calculations
  • Explore relative velocity concepts in aviation
  • Practice problems involving wind effects on flight paths
USEFUL FOR

Aerospace engineers, physics students, pilots, and anyone interested in understanding the impact of wind on flight navigation and velocity calculations.

katiefornald
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Homework Statement


The displacement from London to Rome is 1400 km S 42* E. A wind is blowing with a velocity of 75km/hr east. The pilot wants to fly directly from London to Rome in 3.5 hours. What velocity must the plane have relative to the air?


Homework Equations


Sin, Cos, Tan, Cosign law, Sin law


The Attempt at a Solution


I drew a triangle with a 90 degree angle at the bottom left, on the top left is the peak and labeled london which is 43* and the bottom line says 75 km hr which leads to the right to Rome
 
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welcome to pf!

hi katiefornald! welcome to pf! :smile:
katiefornald said:
I drew a triangle with a 90 degree angle at the bottom left, on the top left is the peak and labeled london which is 43* and the bottom line says 75 km hr which leads to the right to Rome

nooo, wrong triangle :wink:

you need a vector triangle whose three sides are all velocities …

75 east, 400 at 42° (or is it 43 °?), and an unknown velocity

you know one angle and two sides, so you should be able to find the third side :smile:
 

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