How High Can a 100lb Ball Be Thrown Upwards at 100ft/sec?

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SUMMARY

The maximum altitude a 100lb ball can reach when thrown vertically upwards at a velocity of 100 ft/sec is determined using the conservation of energy principle. The relevant equation is h = v² / (2g), where g is the acceleration due to gravity, -32 ft/sec². The weight of the ball does not affect the maximum height, as it cancels out in the calculations. Therefore, the maximum height achieved by the ball is 156.25 feet.

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Dustinsfl
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What is the max altitude when a ball of 100lb is throwing vertically upward with a v = 100 ft/sec?

g = -32ft/sec per sec

I can't figure out how to incorporate the weight.
\[
h(y) = y_0 + v_0t + a\frac{t}{2} = 100t - 16t^2
\]
but can this equation be used? It isn't considering the weight of the object.
 
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Re: throwing a 100lb ball up

I would use conservation of energy here. The initial energy is all kinetic, while the final energy is all gravitational potential:

$$E_i=E_f$$

$$\frac{1}{2}mv^2=mgh$$

$$h=\frac{v^2}{2g}$$

Note: The weight or mass of the object doesn't matter. As you can see here, it simply gets divided out.
 

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