MHB How High Can a 100lb Ball Be Thrown Upwards at 100ft/sec?

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The discussion centers on calculating the maximum altitude a 100lb ball can reach when thrown vertically upward at a velocity of 100 ft/sec. The gravitational acceleration is given as -32 ft/sec². Participants clarify that the weight of the ball does not affect the maximum height, as it cancels out in the energy conservation equation. The relevant formula derived is h = v² / (2g), which indicates that the initial kinetic energy converts entirely into gravitational potential energy at the peak height. Ultimately, the weight of the object is irrelevant in determining the maximum altitude.
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What is the max altitude when a ball of 100lb is throwing vertically upward with a v = 100 ft/sec?

g = -32ft/sec per sec

I can't figure out how to incorporate the weight.
\[
h(y) = y_0 + v_0t + a\frac{t}{2} = 100t - 16t^2
\]
but can this equation be used? It isn't considering the weight of the object.
 
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Re: throwing a 100lb ball up

I would use conservation of energy here. The initial energy is all kinetic, while the final energy is all gravitational potential:

$$E_i=E_f$$

$$\frac{1}{2}mv^2=mgh$$

$$h=\frac{v^2}{2g}$$

Note: The weight or mass of the object doesn't matter. As you can see here, it simply gets divided out.
 
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