How High Did the Catapult Launch the Block on Mars?

  • Thread starter Thread starter pqnd1987
  • Start date Start date
  • Tags Tags
    Velocity
AI Thread Summary
A group of workers on Mars built a catapult and launched a pyramid block with a density of 2400 kg/m³, which later crashed back into the catapult at a velocity of 20 m/s. The discussion revolves around calculating how high the block flew above the catapult, given Mars' gravity of 9.90 m/s² and assuming no air resistance. Participants emphasize that this is a homework question and direct the original poster to the appropriate forum for such inquiries. One user suggests using the velocity equation to determine the time of flight and distance traveled. The conversation highlights the importance of adhering to forum rules regarding homework questions.
pqnd1987
Messages
2
Reaction score
0
Hi I was wondering if anyone had any clue on this question

While sitting around waiting for interior decorators to finish up in the scroll repository, a bunch of bored and mischievous workers decided that they'd build a catapult. When they finally finished, it was able to shoot a projectile straight up into the air. So. in a move which they later regretted, they decided to launch one of the pyramid blocks, which had a density of 2400 kilograms per cubic meter.

When the block crashed back into the catapult, smashing it to pieces, it was determined to have a velocity of 20 meters per second. Assuming that gravity on Mars is exactly 9.90 meters per second squared, the block hit the catapult at the same elevation as it was launched from the catapult, and there was, miraculously, no air resistance acting on the block, how high, in centimeters, did the block fly above the catapult? Please round to the nearest centimeter.
 
Physics news on Phys.org
First, please post homework questions in the appropriate (sub)forum, not in here.

Second, what are your ideas to get things moving?

Daniel.
 
This looks like a homework question. You somehow missed this notice
https://www.physicsforums.com/showthread.php?t=88596
 
Not a homework question. Looks like someone is trying to cheat at Lenny Conundrum.

In any case, they give you the acceleration. You need to first find the time it takes the object to fall by using the velocity equation. Then you can find the distance traveled. I won't do it for you because I want the points. :wink:
 
Last edited:
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top