How Is Destructive Interference Achieved with Two In-Phase Speakers?

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Homework Help Overview

The discussion revolves around the concept of destructive interference produced by two in-phase speakers emitting sound waves. The original poster presents a scenario involving two speakers spaced 3.2 meters apart, both generating a 214 Hz tone, and seeks to determine the shortest distance in front of one speaker where destructive interference occurs.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of wavelength and its relationship to the distance between the speakers. Questions arise about the treatment of the variable m in the context of in-phase speakers and the setup of equations to find points of cancellation.

Discussion Status

Participants are exploring various interpretations of the problem, including the calculation of wavelength and the conditions for destructive interference. Some guidance has been offered regarding the setup of a coordinate system and the mathematical relationship needed to find the distance for destructive interference.

Contextual Notes

There is a mention of potential confusion regarding the variable m and the need to clarify the conditions for complete destructive interference. The original poster has expressed uncertainty about their calculations and the overall approach to the problem.

Gentec
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Good day - I would appreciate some direction. I have done the problem a few different ways and end up with different answers each time - which seems to be reasonable answers to all.

Two speakers are 3.2 m apart and facing the same directions are in phase. They each produce 214 Hz tone. What is the shortest distance directly in front of one speaker where there would be destructive interference?. Take sof sound 343 m/s.

Am i right to treat m =0 seeing it is in phase?

Thank you very much for your time.
 
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What do you mean m=0?

It seems the speakers are 3.2 meters (m) apart.

Have you calculated the wavelength of the sound, and compared it to the separation? Remember the speakers are in phase.

Complete destructive interference is the distance where the peak of one cancels with the trough of the other.

Try to determine the distance to the first trough in front of one of the speakers.
 
Thanks for getting back to me.
I have worked out the lamda to be 1.6 m. Do I need to set up the right equations to have them going opposite directions and see where they sum to zero?
 
if a wave length is 1.6 meters, then since a wave length is half the distance to the other speaker the cancelation point should be?
 
I would say 1.6 m but would that be all there is to the question though.
 
Find the first point (there will be an infinite number of them) such that the difference between the distance from that point to each speaker is exactly half a wavelength.

Set up a coordinate system so that one of the speakers is at (0,0) and the other is at (3.2,0). Assuming that you are directly in front of the first speaker, your position is (0,y) so your distance from that speaker is y and your distance from the other speaker is sqrt(3.22+ y2). Find y so that
sqrt(3.22+ y2)-y= 0.8.

Apparently you did not understand what ComputerGeek said.
 
Thanks for the clarification. Appreciated
 

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