How Is Electric Potential Calculated for a Charged Wire Bent into a Circle?

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SUMMARY

The discussion focuses on calculating the electric potential at a point due to a charged wire bent into a circular shape. The wire has a uniform linear charge density of 2.2 μC/m and a radius of 3.7 m. The relevant equation for electric potential is V = - ∫(E dl), where E represents the electric field. The Coulomb constant used in calculations is 8.98755 × 10^9 N·m²/C², and the solution involves integrating over the circular path of the wire.

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Homework Statement



A wire that has a uniform linear charge density of 2.2 μC/m is bent into the shape as
shown below, with radius 3.7 m.

The Coulomb constant is 8.98755 × 109 N · m2/C2. Find the electrical potential at point p.

Here is the image:
http://s769.photobucket.com/albums/xx339…

(Radius is 3.7 and the distance of line is 7.4)
Answer in units of V.



Homework Equations



V = - integral (E dl)

The Attempt at a Solution



I am at a total loss as to how to solve this. First I thought that since the density is uniform, we won't have to integrate. But I am guessing that integration will be done on this one first for the line and then for the circle. But I am totally stuck as to what to integrate, and what will be the limits of integration.

On this one I spent about 1 hour, but I have reached to no conclusion. I need help on this one! :)

PLEASE HELP! :)

Thanks!
 
Last edited by a moderator:
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okay - time is up now - now I can see the solution...
 

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