How Is EMF Induced in a Loop Within a Solenoid?

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SUMMARY

The discussion focuses on calculating the amplitude of the electromotive force (emf) induced in a small loop placed within a solenoid. The solenoid has 854 turns per centimeter and carries a sinusoidal current with an amplitude of 1.28 A and an angular frequency of 212 rad/s. The correct induced emf is determined to be 0.198 mV, contrasting with an initial incorrect calculation of 6.29E-5 V. The discrepancy arises from the proper application of the derivative of the sinusoidal current function.

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Homework Statement


A small loop with area 6.8 mm^2 is placed in a long solenoid with 854 turns/cm and a sinusoidally varying current w/ amplitude 1.28 A and angular frequency of 212 rad/s. What is the amplitude of the emf induced in the loop?

Homework Equations


\textbf{B}=\mu_0 in
\Phi_B = BA
emf = \frac{d\Phi_B}{dt}

The Attempt at a Solution


Since the current is changing, the emf through the loop should be \mu_0 n A \frac{di}{dt}
If the angular frequency is 212 rad/s, then the current changes by 1.28 A in half a period, which is \frac{\pi}{212} seconds. So the induced emf should be 6.29E-5 V, but the answer is .198 mV.
 
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kinof said:
1.

If the angular frequency is 212 rad/s, then the current changes by 1.28 A in half a period, which is \frac{\pi}{212} seconds. So the induced emf should be 6.29E-5 V, but the answer is .198 mV.

Does not make sense to me.

If the current is i*sin(wt), what is di/dt? The rest of what you did looks OK.

BTW I also get 0.198 mV.
 

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