How Is Heat Distribution Calculated in a Diatomic Ideal Gas Expansion?

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SUMMARY

The discussion focuses on the calculation of heat distribution in a diatomic ideal gas during an isobaric (constant pressure) expansion. It is established that for a diatomic ideal gas, the heat supplied (Q) is related to the change in internal energy through the equation Q = C_p n T, where C_p = 7/2 R. Given that the temperature remains constant during the expansion, 100% of the heat supplied is utilized to increase the internal energy, while 0% is allocated for expansion work.

PREREQUISITES
  • Understanding of thermodynamic principles, specifically isobaric processes.
  • Familiarity with the concept of internal energy in ideal gases.
  • Knowledge of the specific heat capacities, particularly C_p for diatomic gases.
  • Basic algebra for manipulating equations related to heat transfer.
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  • Study the derivation of the first law of thermodynamics in isobaric processes.
  • Learn about the specific heat capacities of different gas types, including monatomic and polyatomic gases.
  • Explore the implications of constant pressure on gas behavior and thermodynamic cycles.
  • Investigate real-world applications of diatomic ideal gas behavior in engineering and physics.
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This discussion is beneficial for students studying thermodynamics, physics enthusiasts, and professionals in engineering fields who require a solid understanding of gas behavior during expansion processes.

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Homework Statement



A diatomic ideal gas expands at constant pressure. What percentage of the heat supplied to the gas is used to increase the internal energy of the gas? what percentage is used to do expansion work?

i know Q=CnT, and in the diatomic ideal gas, C_p= \frac{7}{2} R. but i am so confused that the number of moles, n is not given, and T is also is not given, how get we start with this question...

thx. can someone help me
 
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explain this?Homework Equations Q=CnTC_p= \frac{7}{2} RThe Attempt at a SolutionSince the gas is expanding at constant pressure, its temperature will remain constant. This means that the heat supplied to the gas (Q) will be equal to the increase in the internal energy of the gas (C_p n T). Since the temperature is constant, all of the heat supplied will be used to increase the internal energy. Therefore, 100% of the heat supplied is used to increase the internal energy and 0% is used to do expansion work.
 

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