How Is Heat Transferred Through Skin Layers?

  • Thread starter Thread starter Andrews989
  • Start date Start date
  • Tags Tags
    Heat
Click For Summary
SUMMARY

The discussion focuses on calculating the temperature difference between blood capillaries and the skin surface using the heat transfer equation. Given a heat transfer rate of 240 J/s, a thermal conductivity of 0.2 J/(s·m·°C), a surface area of 1.6 m², and a distance of 2.0×10−3 m, the equation Q/t = k * A * ΔT / L is applied. Substituting the provided values yields a temperature difference of 1.5°C between the capillaries and the skin surface.

PREREQUISITES
  • Understanding of heat transfer principles
  • Familiarity with the equation Q = k * A * ΔT / L
  • Knowledge of thermal conductivity units
  • Basic algebra for solving equations
NEXT STEPS
  • Study the concept of thermal conductivity in biological tissues
  • Learn about the implications of heat transfer in human physiology
  • Explore advanced heat transfer equations and their applications
  • Investigate the role of different skin layers in thermoregulation
USEFUL FOR

Students in physics or biology, healthcare professionals interested in thermoregulation, and anyone studying heat transfer in biological systems.

Andrews989
Messages
7
Reaction score
0

Homework Statement



The amount of heat per second conducted from the blood capillaries beneath the skin to the
surface is 240 J. The energy is transferred a distance of 2.0×10−3mthrough a body whose surface area is 1.6 m2. Assuming that the thermal conductivity is that of body fat 0.2 J /(s ⋅m⋅o C) , determine the temperature difference between the capillaries and the surface of the skin.

So k = .2
A = 1.6 m^2
L = 2.0 x 10^-3m

I'm not sure what the 240 J goes as? Is that Q?


Homework Equations



This is basically where I'm stuck... I'm not sure what equation to use.

I was thinking possibly Q = k * A * change in T * time all divided by L ... but there's no mention of time?


The Attempt at a Solution

 
Physics news on Phys.org
You wrote down the right equation. Notice that give you a rate of heat transfer so you can divide time over to the left side of the equation.

Then it's just a substitution of information problem.
 
AtticusFinch said:
You wrote down the right equation. Notice that give you a rate of heat transfer so you can divide time over to the left side of the equation.

Then it's just a substitution of information problem.

So...

Q/t = k * A * change in T / L

240 = .2 * 1.6 * change in T / 2 X 10^-3

So the answer would be 1.5 degrees?

I think that's right... thanks
 

Similar threads

Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
969
  • · Replies 1 ·
Replies
1
Views
2K
Replies
8
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K