How Is Net Work Calculated in a Thermodynamic Cycle?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
3 replies · 3K views
nrc_8706
Messages
69
Reaction score
0
Wbc=0 Wab=-3315.4J Wca=nRTLn(Va/Vc)=-2108.98

The net heat added to the gas for the entire cycle is 1200J. Determine the net work done by the gas on its surroundings for the entire cycle.


Don't you just add the works?
 

Attachments

  • 01-18-2006 05;29;34PM.JPG
    01-18-2006 05;29;34PM.JPG
    37.2 KB · Views: 466
Physics news on Phys.org
why can't i see the attachments?
01-18-2006 05;29;34PM.JPG
 
does anyone know how to do this?:confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused:
 
nrc_8706 said:
why can't i see the attachments?
View attachment 6344

Because they have to be approved by a moderator. We've had people attach porn in the past, so every attachment goes through a moderation queue. I've just approved all your attachments.

Wab=-3315.4J Wca=nRTLn(Va/Vc)=-2108.98

Are you sure about that? ab is an expansion, while ca is a compression. [itex]\int p dV[/itex] has a different sign along each path.