How Is Net Work Calculated in a Thermodynamic Cycle?

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Homework Help Overview

The discussion revolves around calculating net work in a thermodynamic cycle, specifically focusing on the work done during different segments of the cycle and the relationship between heat and work in thermodynamics.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of net work by considering the individual works done in different segments of the cycle. There is a question about whether the works can simply be added together. Some participants also express confusion about the signs of the work values based on the nature of the processes (expansion vs. compression).

Discussion Status

The discussion is ongoing, with participants raising questions about the calculation methods and the visibility of attachments. Some guidance has been provided regarding the approval process for attachments, but there is no clear consensus on the calculation of net work.

Contextual Notes

There are mentions of attachments that require moderator approval, which may be relevant to the discussion. Additionally, there is a focus on the signs of work related to the processes in the thermodynamic cycle.

nrc_8706
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Wbc=0 Wab=-3315.4J Wca=nRTLn(Va/Vc)=-2108.98

The net heat added to the gas for the entire cycle is 1200J. Determine the net work done by the gas on its surroundings for the entire cycle.


Don't you just add the works?
 

Attachments

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why can't i see the attachments?
01-18-2006 05;29;34PM.JPG
 
does anyone know how to do this?:confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused:
 
nrc_8706 said:
why can't i see the attachments?
View attachment 6344

Because they have to be approved by a moderator. We've had people attach porn in the past, so every attachment goes through a moderation queue. I've just approved all your attachments.

Wab=-3315.4J Wca=nRTLn(Va/Vc)=-2108.98

Are you sure about that? ab is an expansion, while ca is a compression. [itex]\int p dV[/itex] has a different sign along each path.
 

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