How Is Net Work Calculated in a Thermodynamic Cycle?

nrc_8706 · Feb 19, 2006

Wbc=0 Wab=-3315.4J Wca=nRTLn(Va/Vc)=-2108.98

The net heat added to the gas for the entire cycle is 1200J. Determine the net work done by the gas on its surroundings for the entire cycle.

Don't you just add the works?

nrc_8706 · Feb 19, 2006

why can't i see the attachments?

PV diagram of a closed cycle abca for an ideal gas: a horizontal line a to b at about 12 x 10^4 Pa, a vertical line b down to c at about 47 x 10^-3 m^3, and a curved path c back to a labeled 301 ± 1 K isotherm. Axes: Volume (x 10^-3 m^3), Pressure (x 10^4 Pa).

nrc_8706 · Feb 19, 2006

does anyone know how to do this?

quantumdude · Feb 20, 2006

nrc_8706 said:

why can't i see the attachments?
View attachment 6344

Because they have to be approved by a moderator. We've had people attach porn in the past, so every attachment goes through a moderation queue. I've just approved all your attachments.

Wab=-3315.4J Wca=nRTLn(Va/Vc)=-2108.98

Are you sure about that? ab is an expansion, while ca is a compression. [itex]\int p dV[/itex] has a different sign along each path.

How Is Net Work Calculated in a Thermodynamic Cycle?

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