How Is Net Work Calculated in a Thermodynamic Cycle?

nrc_8706
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Wbc=0 Wab=-3315.4J Wca=nRTLn(Va/Vc)=-2108.98

The net heat added to the gas for the entire cycle is 1200J. Determine the net work done by the gas on its surroundings for the entire cycle.


Don't you just add the works?
 

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does anyone know how to do this?:confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused: :confused:
 
nrc_8706 said:
why can't i see the attachments?
View attachment 6344

Because they have to be approved by a moderator. We've had people attach porn in the past, so every attachment goes through a moderation queue. I've just approved all your attachments.

Wab=-3315.4J Wca=nRTLn(Va/Vc)=-2108.98

Are you sure about that? ab is an expansion, while ca is a compression. \int p dV has a different sign along each path.
 

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